Dental Crown Cost in Indiana
Dental crown in Indiana costs about $1,170 for one crown, with most prices from $720 to $1,980.
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Dental Crown price in Indiana
| Low | Typical | High | |
|---|---|---|---|
| Indiana | $720 | $1,170 | $1,980 |
| US national | $800 | $1,300 | $2,200 |
Regional cost index used for Indiana: 0.90 (1.00 is the US average). That ranks Indiana number 9 of 51 from lowest to highest cost. The low end of the range is typical of a clinic or provider that competes on price; the high end is typical of a hospital, a specialist or a big-city practice. Prices in your own town can sit outside the range, so call two or three providers and ask for the self-pay price.
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Ways to lower the bill
- Insurance often covers about half after the deductible.
- Ask for the cash or self-pay price; it is often lower than the billed price.
- Compare two or three providers, including dental schools or low-cost clinics where they exist.
- Ask about payment plans and whether an HSA or FSA can be used.
Frequently asked questions
How much is dental crown in Indiana?
About $1,170 (range $720 to $1,980).
Does insurance cover it?
Insurance often covers about half after the deductible.
Sources and method
- Bureau of Economic Analysis: regional price parities
- Estimates only, not medical advice or a quote
Page last updated November 2026. See our editorial policy and disclaimer.